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@johncarlosbaez @fabgenovese @hjrrockies @CreeepyJoe Seeing as 1#x=1, we will need to remove the number that behaves like ∞. Restrict to x>1 and we'll have a group, with x#(e^(1/ln x))=x. Fun puzzle.Permalink On twitter.com
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@johncarlosbaez @fabgenovese @hjrrockies @CreeepyJoe Ooh, restricting x>1 gives a copy of R, but for added fun it seems that x>0&x≠1 gives a copy of R⊕Z_2. 🙃On twitter.com