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@mrweathers @matthematician I like the picture but I feel like I'd prefer Δf and Δg over f' and g' here. Then Δ(fg)=(Δf)g+f(Δg)+(Δf)(Δg), and Δ(fg)/Δx=(Δf/Δx)g+f(Δg/Δx)+(Δf)(Δg)/Δx, with (Δf)(Δg)/Δx vanishing (since (Δf/Δx) is finite and Δg goes to zero).Permalink On twitter.com
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@mrweathers @matthematician (And I should clarify, I really really like the picture and will steal it in the future.)On twitter.com