StevenXClontz’s avatarStevenXClontz’s Twitter Archive—№ 6,638

  1. …in reply to @sbagley
    @sbagley Also the step that seems to assume log(1+n/100) \approx n/100 is doing a lot of heavy lifting here.
    On twitter.com Twitter logo StevenXClontz’s avatar ❤️ 2 Favorites Mood 0
    1. …in reply to @StevenXClontz
      @sbagley (I guess it's because log(1+0/100)=0/100 and d/dx(log(1+x/100))=1/(100+x) and d/dx(x/100)=1/100.)
      Permalink On twitter.com Twitter logo StevenXClontz’s avatar ❤️ 1 Favorite Mood 0