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@siwelwerd Flow/work is defined as ∫F·Tds=∫F·dr, so nat defn for flux is ∫F·Nds=∫F/κ·dT. But this measures *inward*! 1/n
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@siwelwerd So who's the jerk that defined flux as ∫F·nds, where n gives the *outward* unit normals? 2/2
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@siwelwerd Also flux= ∫Ndx-Mdy would have nice symmetry with curl·k=N_x-M_y. 3/3
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@siwelwerd Yeah, weak rant. I do prefer orienting my surfaces with outward unit vectors and orienting my planar regions with k, so it's not all bad.